• Category Archives: HVAC Calculations

Magic Number 2652 Explained

Testing a capacitor under load means testing it while it is in an operating circuit. To do this you measure the operating capacitor amp draw and voltage and then apply them to the formula

Why does this work and where does the 2652 come from? To answer these questions, we need to understand what a capacitor does in an AC motor circuit.

What Does a Capacitor Do?

A run capacitor’s job is to add enough capacitive reactance to offset the inductive reactance of the winding it is in series with. Current in an inductive (magnetic) load lags the voltage. This means that the current peaks AFTER the voltage. Since the current and voltage are out of phase with each other, they don’t work together, causing inefficiency. Adding a capacitor in series with an inductive (magnetic) load helps correct this because capacitors cause the current to peak BEFORE the voltage. The amount of capacitive reactance needed depends upon the inductive reactance of the motor.

Like resistance, capacitive reactance is measured in ohms. The capacitive reactance produced by a particular capacitor varies with both the frequency of the AC current and the microfarad capacity of the capacitor. Higher frequencies and higher microfarad capacity both decrease capacitive reactance. The formula is

 This means that capacitive reactance is equal to the inverse of the product of 2 x pi x frequency x Farad rating. Through the magic of algebra we know that we can swap the XC (capacitive reactance) and C (capacitance) terms to get our formula for capacitance. That gives us the formula

 This can be rewritten as  

In this formula, 2π is a mathematical expression for a cycle. Recalling that the circumference of a circle is twice the radius times π, the expression 2π represents a complete turn of a circle if we are not concerned with the circle’s radius. Frequency is represented by f, which is always 60 cycles in North America. Together, 1/2πf calculates the effect of frequency on capacitive reactance.

works out to 0.00265258 for 60 cycle power. This would produce an answer in Farads, but we normally work with microfarads. Multiplying this by 1000 to get 2652.58 produces an answer in microfarads. This is usually rounded to 2652.

What about the capacitive reactance, XC? Remember that capacitive reactance is measured in ohms and that ohms can be found by dividing volts by amps. So we can substitute the capacitor voltage divided by the capacitor amps for the capacitive reactance. However, since 1/XC is the inverse of capacitive reactance, the fraction is flipped to perform the multiplication, placing amps on top. Together the two terms become

Airflow by the Numbers

You may be familiar with the formula: BTUH = CFM x ΔT x 1.08. This same formula is often rearranged to use for determining airflow by measuring the heat input and temperature rise: CFM=BTUH/( ΔT x 1.08). To get the BTU per hour (BTUH) with electric strips you use the formula BTUH = volts x amps x 3.41 BTUH/watt. Together the formula looks like: CFM = (volt x amps x 3.41)/ ( ΔT x 1.08). The factor 3.41 comes from physics. It is the number of BTUs produced by one watt-hour of electricity. But where does the 1.08 factor come from? The “magic number” 1.08 is convenience factor. It is basically a bunch of math combined into one factor as a short cut.

You may recall that the specific heat formula is used for changing the temperature of something. The specific heat formula is
BTU = weight x ΔT x Specific Heat
This has one big problem, we don’t measure airflow by weight, but by volume. AHRI Standard air weighs 0.075 pounds per cubic foot. We can convert air volume to air weight by multiplying the air volume by 0.075 lbs/ft3. Another issue is that we tend to measure airflow by the minute and BTUs by the hour. You can fix that by multiplying times 60. Finally, we need the specific heat of air, which is 0.24. When you multiply the air volume by 0.075 to turn CFM into pounds per minute, multiply pounds per minute by 60 to get pounds per hour, and multiply by the specific heat of air 0.24, you end up with 1.08 (60 x .075 x 0.24 = 1.08). The number is not really a constant because the density of the air varies a lot with temperature, which changes the “magic number.” This formula is accurate for dry air at around 70°F, but it is NOT accurate when the air temperature gets very much colder or warmer than 70°F. For example, 1.08 really does not work with flue gas or airflow in freezers because the air density has changed, which changes the convenience factor. At 400°F the air only weighs 0.043 lbs/ft3, changing the convenience factor to 0.62 (60 x 0.043 x 0.24 = 0.62). At 0°F, air weighs 0.086 lbs/ft3, changing the convenience factor to 1.24 (60 x 0.086 x 0.24 = 1.24). Air density also changes with elevation and humidity, although the change due to humidity is small. Even the specific heat of air changes as the air temperature changes, but again, the changes are small. This is all to say that if you are dealing with air around room temperature, feel free to use the 1.08 convenience factor. However, if you are dealing with air at a much different temperature, you should look up the weight of air at the temperature you are working with. The table below lists the weight of a cubic foot of air at different temperatures and provides a reworked convenience factor so that you can perform correct air calculations at temperatures other than 70°F.

TemperatureWeight lb/ft3Convenience FactorTemperatureWeight lb/ft3Convenience Factor
0°F0.086251.24175°F0.062550.90
10°F0.084411.22200°F0.060180.87
20°F0.082651.19225°F0.057970.84
30°F0.080961.17250°F0.055910.81
40°F0.079351.14275°F0.053990.79
50°F0.077801.12300°F0.052190.76
60°F0.076311.10325°F0.050510.74
70°F0.074871.08350°F0.048940.72
80°F0.073491.06375°F0.047460.70
90°F0.072171.04400°F0.046080.68
100°F0.070891.02425°F0.044780.66
110°F0.069651.00450°F0.043570.64
120°F0.068460.99475°F0.042420.63
130°F0.067300.97500°F0.041340.61
140°F0.066190.95525°F0.040310.60
150°F0.065110.94550°F0.039330.59
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